NEET 2026 Physics Motional EMF MCQ Question
A rectangular wire loop of sides 8 cm and 3 cm with a small cut, is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the plane of the loop. The emf developed across the cut, if the velocity of the loop is 2 cm s⁻¹, in a direction normal to the shorter side of the loop, will be:
4.8 × 10⁻⁴ volt
1.2 × 10⁻⁴ volt
1.3 × 10⁻⁴ volt
1.8 × 10⁻⁴ volt
Correct Answer
Detailed Explanation
Induced emf across the shorter side is given by E_induced = Bvl. Substituting the values, we get E_induced = 0.3 × 2 × 10⁻² × 3 × 10⁻² = 1.8 × 10⁻⁴ V.
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