MarksRiser
MarksRiser
NEET2023Physics-Electromagnetism

NEET 2023 Physics Inductance MCQ Question

Type: MCQ-numerical-Medium-Class 12

The magnetic energy stored in an inductor of inductance 4 μH carrying a current of 2 A is:

A

4 mJ

B

8 mJ

C

8 μJ

D

4 μJ

Correct Answer

Option C

Detailed Explanation

The energy stored in an inductor is given by the formula E=12LI2E = \frac{1}{2} L I^2. Substituting L=4×10−6 HL = 4 \times 10^{-6} \, H and I=2 AI = 2 \, A, we get E=12×4×10−6×4=8×10−6 J=8 μJE = \frac{1}{2} \times 4 \times 10^{-6} \times 4 = 8 \times 10^{-6} \, J = 8 \, \mu J.

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