NEET Physics Faraday's Laws MCQ Question
A coil with 50 turns is placed in a magnetic field that changes from 0.2 T to 0.5 T in 0.1 seconds. The area of the coil is 0.1 m² and the angle between the magnetic field and the normal to the coil is 0°. What is the magnitude of the induced emf in the coil?
15 V
30 V
50 V
75 V
Correct Answer
Detailed Explanation
Using Faraday's law, the induced emf is calculated as ε = -N * (ΔΦ/Δt). Here, ΔΦ = (Bf - Bi) * A = (0.5 T - 0.2 T) * 0.1 m² = 0.03 Wb. Thus, ε = -50 * (0.03 Wb / 0.1 s) = -15 V. The negative sign indicates direction, so the magnitude is 15 V.
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