Physics-Electric Field

NEET Physics Electric Field MCQ Question

Type: MCQ-diagram based-Easy-Class 12

Imagine a diagram of a uniformly charged cylindrical surface with charge density λ\lambda. The electric field EE at a point outside the cylinder depends on the radial distance rr from the axis of the cylinder. Which expression correctly represents the magnitude of the electric field EE at this point?

Question diagram
A

E=λ2πϵ0rE = \frac{\lambda}{2\pi \epsilon_0 r}

B

E=λ4πϵ0rE = \frac{\lambda}{4\pi \epsilon_0 r}

C

E=2λπϵ0rE = \frac{2\lambda}{\pi \epsilon_0 r}

D

E=λπϵ0r2E = \frac{\lambda}{\pi \epsilon_0 r^2}

Correct Answer

Option A

Detailed Explanation

The correct expression is E=λ2πϵ0rE = \frac{\lambda}{2\pi \epsilon_0 r}, as derived using Gauss's law for a cylindrical surface. This expression indicates that the electric field magnitude depends inversely on the radial distance rr.

Found an issue with this question?