Imagine a diagram of a uniformly charged cylindrical surface with charge density $ \lambda $. The electric field $ E $ at a point outside the cylinder depends on the radial distance $ r $ from t

Question

Imagine a diagram of a uniformly charged cylindrical surface with charge density $\lambda$ . The electric field $E$ at a point outside the cylinder depends on the radial distance $r$ from the axis of the cylinder. Which expression correctly represents the magnitude of the electric field $E$ at this point?

A

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

B

$E = \frac{\lambda}{4\pi \epsilon_0 r}$

C

$E = \frac{2\lambda}{\pi \epsilon_0 r}$

D

$E = \frac{\lambda}{\pi \epsilon_0 r^2}$

Accepted Answer

$ E = \frac{\lambda}{2\pi \epsilon_0 r} $

Answer

$ E = \frac{\lambda}{4\pi \epsilon_0 r} $

Answer

$ E = \frac{2\lambda}{\pi \epsilon_0 r} $

Answer

$ E = \frac{\lambda}{\pi \epsilon_0 r^2} $

NEET Physics Electric Field MCQ Question

Correct Answer

Detailed Explanation

Related Questions

More from Electric Field

More from

Explore More Questions