In the diagram shown above, if the charge density $\lambda$ is doubled, how does the electric field $E$ at a point $r$ on the Gaussian surface change?
A
E also doubles.
B
E remains the same.
C
E becomes half.
D
E quadruples.

Question

In the diagram shown above, if the charge density $ \lambda $ is doubled, how does the electric field $ E $ at a point $ r $ on the Gaussian surface change?

Accepted Answer

E also doubles.

Answer

E remains the same.

Answer

E becomes half.

Answer

E quadruples.

NEET Physics Electric Field MCQ Question

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