Physics-Coulomb's Law
NEET Physics Coulomb's Law MCQ Question
Type: MCQ-numerical-Hard-Class 12
Two point charges q1 = 2 μC and q2 are placed 0.3 m apart. If the electrostatic force between them is 0.06 N, what is the magnitude of q2?
A
0.027 μC
B
0.134 μC
C
0.100 μC
D
0.067 μC
Correct Answer
Option D
Detailed Explanation
Using Coulomb's law F = k(q1*q2)/r², with F = 0.06 N, q1 = 2 μC, r = 0.3 m, and k = 8.98755 x 10^9 N m²/C², solving for q2 gives approximately 0.067 μC.
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