NEET Physics Coulomb's Law MCQ Question
Two point charges, each of +1.6 × 10^-19 C, are placed 1 nm apart in a vacuum. What is the magnitude of the electrostatic force between them?
2.3 × 10^-10 N
2.3 × 10^-8 N
8.987 × 10^-9 N
1.6 × 10^-9 N
Correct Answer
Detailed Explanation
The magnitude of force is calculated using Coulomb's Law: F = k * |q1 * q2| / r^2. With k = 8.987 × 10^9 Nm^2/C^2 and q1 = q2 = 1.6 × 10^-19 C, r = 1 nm = 10^-9 m, the force is 2.3 × 10^-8 N.
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