NEET Physics Coulomb's Law MCQ Question
Two point charges, each of magnitude 1.6 × 10^-19 C, are placed 10^-10 meters apart in vacuum. What is the magnitude of the force between them?
2.3 × 10^-8 N
9.0 × 10^-9 N
1.5 × 10^-9 N
7.2 × 10^-8 N
Correct Answer
Detailed Explanation
Using Coulomb's law, the force F = k * |q1 * q2| / r^2 where k = 8.987 × 10^9 Nm^2/C^2, q1 = q2 = 1.6 × 10^-19 C, and r = 10^-10 m. Substituting these values gives F = 2.3 × 10^-8 N.
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