Physics-Coulomb's Law
NEET Physics Coulomb's Law MCQ Question
Type: MCQ-numerical-Easy-Class 12
Two point charges, each of magnitude 1.6 × 10^-19 C, are placed 10^-10 meters apart in vacuum. What is the magnitude of the force between them?
A
2.3 × 10^-8 N
B
9.0 × 10^-9 N
C
1.5 × 10^-9 N
D
7.2 × 10^-8 N
Correct Answer
Option A
Detailed Explanation
Using Coulomb's law, the force F = k * |q1 * q2| / r^2 where k = 8.987 × 10^9 Nm^2/C^2, q1 = q2 = 1.6 × 10^-19 C, and r = 10^-10 m. Substituting these values gives F = 2.3 × 10^-8 N.
Found an issue with this question?