NEET Physics Photoelectric Effect MCQ Question
What is the stopping potential required to stop the most energetic photoelectrons emitted when ultraviolet light of frequency 8 × 10^14 Hz is incident on a metal with a work function of 3 eV?
1.3 V
2.3 V
3.3 V
4.3 V
Correct Answer
Detailed Explanation
The stopping potential is given by eV₀ = hf - φ, where h is Planck's constant, f is the frequency, and φ is the work function. Using h = 4.1357 × 10^(-15) eV·s, f = 8 × 10^14 Hz, and φ = 3 eV, we find V₀ = (4.1357 × 10^(-15) × 8 × 10^14) - 3 = 2.3 V.
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