NEET Physics Photoelectric Effect MCQ Question
If the frequency of incident light on a caesium metal surface is 6 × 10^14 Hz and the work function is 2.14 eV, what is the maximum kinetic energy of the emitted electrons?
37 eV
23 eV
40 eV
16 eV
Correct Answer
Detailed Explanation
The maximum kinetic energy (K_max) is calculated using Einstein’s photoelectric equation: K_max = h*f - φ, where h is Planck's constant, f is the frequency of incident light, and φ is the work function. Here, K_max = (6.626 × 10^-34 J s * 6 × 10^14 Hz) - 2.14 eV = 2.37 eV.
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