Physics-(general)
NEET Physics (general) Match the Following Question
Type: Match the Following-match the column-Medium-Class 12
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Work function of caesium | (i) 6.63 × 10^-34 J s |
| (b) Threshold frequency | (ii) 2.14 eV |
| (c) Energy of photon | (iii) 4.14 × 10^14 Hz |
| (d) Maximum kinetic energy | (iv) eV = hf - φ |
A
a-ii, b-iii, c-i, d-iv
B
a-i, b-ii, c-iv, d-iii
C
a-ii, b-iv, c-i, d-iii
D
a-iv, b-ii, c-i, d-iii
Correct Answer
Option A
Detailed Explanation
The work function of caesium is 2.14 eV, the threshold frequency is calculated using the formula hf = φ, where h is Planck's constant (6.63 × 10^-34 J s), and the relationship between photon energy and frequency is E = hf. The maximum kinetic energy is represented by the equation eV = hf - φ.
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