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Physics-de Broglie Wavelength

NEET Physics de Broglie Wavelength MCQ Question

Type: MCQ-diagram based-Hard-Class 12

Imagine a diagram showing a wave-like pattern associated with a particle moving at a specific velocity. The particle's momentum is labeled as pp and its de Broglie wavelength as λ\lambda. Which of the following correctly describes the relationship depicted between the particle's momentum and its de Broglie wavelength?

Question diagram
A

The de Broglie wavelength is directly proportional to the particle's momentum.

B

The de Broglie wavelength is inversely proportional to the particle's momentum.

C

The de Broglie wavelength remains constant irrespective of the particle's momentum.

D

The de Broglie wavelength is independent of both the particle's momentum and velocity.

Correct Answer

Option B

Detailed Explanation

The de Broglie wavelength λ\lambda is given by λ=hp\lambda = \frac{h}{p}, indicating an inverse relationship with momentum pp. This is noted in the NCERT context where λ=hmv\lambda = \frac{h}{m v}.

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