Physics-de Broglie Wavelength

NEET Physics de Broglie Wavelength MCQ Question

Type: MCQ-diagram based-Easy-Class 12

In a diagram representing the de Broglie wavelength of particles, a particle with mass m and velocity v is shown. Which equation correctly represents the de Broglie wavelength λ\lambda of this particle?

Question diagram
A

λ=hmv\lambda = \frac{h}{mv}

B

λ=mvh\lambda = \frac{mv}{h}

C

λ=hm+v\lambda = \frac{h}{m+v}

D

λ=h×mv\lambda = h \times mv

Correct Answer

Option A

Detailed Explanation

The de Broglie wavelength λ\lambda is given by λ=hp\lambda = \frac{h}{p}, where p=mvp = mv is the momentum of the particle. Hence, λ=hmv\lambda = \frac{h}{mv}.

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