NEET 2026 Physics Wheatstone Bridge MCQ Question

Topic: Current Electricity → Wheatstone Bridge Difficulty: 🟡 Medium

✅ Ans: 2 A

Total wire resistance $=4\Omega$, so each side:

$$R=\frac44=1\Omega$$

The two paths from A to C are:

$$A-B-C=1+1=2\Omega$$ $$A-D-C=1+1=2\Omega$$

Since the circuit is symmetric, B and D are at the same potential.

Therefore, no current flows through the $2\Omega$ diagonal resistor.

$$R_{eq}=2\parallel2=1\Omega$$ $$I=\frac{V}{R_{eq}}=\frac{2}{1} =\boxed{2A}$$

🧠 NEET Trick

Equal arms → B and D equipotential → diagonal branch carries zero current.