Consider a cylindrical conductor with length $l$ and cross-sectional area $A$ . The resistivity of the material is $\rho$ . Which equation correctly represents the resistance $R$ of this conductor?
A
R = $\rho \frac{l}{A}$
B
R = $\frac{A}{\rho l}$
C
R = $\frac{l}{\rho A}$
D
R = $\rho \frac{A}{l}$

Question

Consider a cylindrical conductor with length $l$ and cross-sectional area $A$ . The resistivity of the material is $\rho$ . Which equation correctly represents the resistance $R$ of this conductor?

A

R = $\rho \frac{l}{A}$

B

R = $\frac{A}{\rho l}$

C

R = $\frac{l}{\rho A}$

D

R = $\rho \frac{A}{l}$

Accepted Answer

R = $ \rho \frac{l}{A} $

Answer

R = $ \frac{A}{\rho l} $

Answer

R = $ \frac{l}{\rho A} $

Answer

R = $ \rho \frac{A}{l} $

NEET Physics Resistance & Resistivity MCQ Question

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