NEET2016Physics-Current Electricity
NEET 2016 Physics Potentiometer MCQ Question
Type: MCQ-numerical-Medium-Class 12
A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series’ first to support one another and then in opposite direction. The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of emf’s is
A
3 : 4
B
3 : 2
C
5 : 1
D
5 : 4
Correct Answer
Option B
Detailed Explanation
The ratio of the emfs is determined by the balance points. The ratio is the length of the wire in the first case to the length in the second case, which is 50/10 = 5:1.
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