NEET2014Physics-Current Electricity

NEET 2014 Physics Potentiometer MCQ Question

Type: MCQ-conceptual-Medium-Class 12

A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an e.m.f. of 2.0 V and a negligible internal resistance. The potentiometer wire itself is 4 m long. When the resistance, R, connected across the given cell, has values of i. Infinity ii. 9.5 Ω, the balancing lengths, on the potentiometer wire are found to be 3 m and 2.85 m, respectively. The value of internal resistance of the cell is

A

0.25 Ω

B

0.95 Ω

C

0.5 Ω

D

0.75 Ω

Correct Answer

Option D

Detailed Explanation

Using the formula for internal resistance, r = R(l₁ - l₂)/l₂, where l₁ and l₂ are the balancing lengths. Substituting the given values, r = 9.5(3 - 2.85)/2.85 = 0.75 Ω.

Found an issue with this question?

Related Questions