NEET Physics Ohm's Law MCQ Question with Solution

Two cells with emfs $\varepsilon_1 = 2V$ and $\varepsilon_2 = 3V$ and internal resistances $r_1 = 1\Omega$ and $r_2 = 2\Omega$ are connected in parallel. What is the equivalent emf $\varepsilon_{eq}$ of the combination?

A

33 V

B

67 V

C

00 V

D

50 V

Correct Answer

Option A

Detailed Explanation

Using equation (3.54) from the NCERT context, the equivalent emf $\varepsilon_{eq}$ is calculated by $\varepsilon_{eq} = \frac{\varepsilon_1 r_2 + \varepsilon_2 r_1}{r_1 + r_2} = \frac{2 \times 2 + 3 \times 1}{1 + 2} = 2.33$ V.

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