Physics-Ohm's Law

NEET Physics Ohm's Law MCQ Question

Type: MCQ-numerical-Medium-Class 12

Two cells with emfs ε1=2V\varepsilon_1 = 2V and ε2=3V\varepsilon_2 = 3V and internal resistances r1=1Ωr_1 = 1\Omega and r2=2Ωr_2 = 2\Omega are connected in parallel. What is the equivalent emf εeq\varepsilon_{eq} of the combination?

A

33 V

B

67 V

C

00 V

D

50 V

Correct Answer

Option A

Detailed Explanation

Using equation (3.54) from the NCERT context, the equivalent emf εeq\varepsilon_{eq} is calculated by εeq=ε1r2+ε2r1r1+r2=2×2+3×11+2=2.33\varepsilon_{eq} = \frac{\varepsilon_1 r_2 + \varepsilon_2 r_1}{r_1 + r_2} = \frac{2 \times 2 + 3 \times 1}{1 + 2} = 2.33 V.

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