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Physics-Kirchhoff's Laws

NEET Physics Kirchhoff's Laws MCQ Question

Type: MCQ-diagram based-Hard-Class 12

Consider a circuit consisting of two loops with three resistors R1,R2,R_1, R_2, and R3R_3 and two batteries with emfs ε1\varepsilon_1 and ε2\varepsilon_2. If Kirchhoff's loop rule is applied to both loops, what is the correct expression for the loop containing R1,R2,ε1,R_1, R_2, \varepsilon_1, and ε2\varepsilon_2?

Question diagram
A

ε1−I1R1−I2R2+ε2=0\varepsilon_1 - I_1 R_1 - I_2 R_2 + \varepsilon_2 = 0

B

ε1−I1R1−I2R2−ε2=0\varepsilon_1 - I_1 R_1 - I_2 R_2 - \varepsilon_2 = 0

C

ε1+I1R1+I2R2−ε2=0\varepsilon_1 + I_1 R_1 + I_2 R_2 - \varepsilon_2 = 0

D

−ε1+I1R1+I2R2+ε2=0-\varepsilon_1 + I_1 R_1 + I_2 R_2 + \varepsilon_2 = 0

Correct Answer

Option B

Detailed Explanation

Kirchhoff's loop rule states that the algebraic sum of emfs and potential drops (products of current and resistance) in any closed loop is zero. In this loop, the potential difference across R1R_1 and R2R_2 are I1R1I_1 R_1 and I2R2I_2 R_2 respectively, and the emfs ε1\varepsilon_1 and ε2\varepsilon_2 are subtracted according to their orientation.

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