Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-diagram based-Easy-Class 12

Consider a diagram showing two cells connected in parallel between points B1 and B2. If replaced by a single cell of equivalent emf and internal resistance, which equation correctly represents the equivalent emf εeq\varepsilon_{eq} in terms of ε1\varepsilon_1, ε2\varepsilon_2, r1r_1, and r2r_2?

Question diagram
A

εeq=ε1r2+ε2r1r1+r2\varepsilon_{eq} = \frac{\varepsilon_1 r_2 + \varepsilon_2 r_1}{r_1 + r_2}

B

εeq=ε1+ε22\varepsilon_{eq} = \frac{\varepsilon_1 + \varepsilon_2}{2}

C

εeq=ε1+ε2\varepsilon_{eq} = \varepsilon_1 + \varepsilon_2

D

εeq=ε1ε2\varepsilon_{eq} = \varepsilon_1 \varepsilon_2

Correct Answer

Option A

Detailed Explanation

The equivalent emf for two cells in parallel is calculated using εeq=ε1r2+ε2r1r1+r2\varepsilon_{eq} = \frac{\varepsilon_1 r_2 + \varepsilon_2 r_1}{r_1 + r_2}, as given by Eq. (3.54) in the NCERT context.

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