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Physics-Bohr Model

NEET Physics Bohr Model MCQ Question

Type: MCQ-numerical-Hard-Class 12

In the Bohr model, when an electron transitions from an initial energy level ni=4n_i = 4 to a final energy level nf=2n_f = 2, what is the frequency of the emitted photon if the energy difference Eni−EnfE_{ni} - E_{nf} is 2.55 eV?

A

6.16 x 10^14 Hz

B

5.15 x 10^14 Hz

C

25 x 10^14 Hz

D

75 x 10^14 Hz

Correct Answer

Option A

Detailed Explanation

The frequency of the emitted photon is calculated using u=Eni−Enfh u = \frac{E_{ni} - E_{nf}}{h}. With Eni−Enf=2.55E_{ni} - E_{nf} = 2.55 eV and Planck's constant h=4.14×10−15h = 4.14 \times 10^{-15} eV·s, the frequency u u is approximately 6.16×10146.16 \times 10^{14} Hz.

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