Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Easy-Class 12
In a series RLC circuit, if the resistance R is doubled from 100 Ω to 200 Ω while the inductance L remains at 1.00 mH, how does the resonant current amplitude change?
A
It is halved.
B
It remains the same.
C
It doubles.
D
It is quadrupled.
Correct Answer
Option A
Detailed Explanation
At resonance, the current amplitude is inversely proportional to the resistance R. When R is doubled, the current amplitude is halved.
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