NEET Physics Work-Energy Theorem MCQ Question
A block of mass m = 1 kg is moving on a horizontal surface with an initial speed v_i = 2 m/s. It enters a rough patch where the retarding force F_r on the block is inversely proportional to x, given by F_r = -k/x for 0.1 < x < 2.01 m with k = 0.5 J. What is the final kinetic energy of the block as it exits the rough patch at x = 2.01 m?
0 J
5 J
0 J
0.5 J
Correct Answer
Detailed Explanation
Using the work-energy theorem, the work done by the force is equal to the change in kinetic energy. Integrating the force from x = 0.1 to x = 2.01 m gives the work done, which is used to find the final kinetic energy.
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