NEET Physics Work-Energy Theorem MCQ Question
A block of mass 1 kg, initially moving at 2 m/s on a smooth horizontal surface, enters a rough patch where the retarding force is inversely proportional to its position x. Given that the force is F_r = -0.5/x for 0.1 < x < 2.01 m, what is the final kinetic energy of the block after crossing the patch?
25 J
0 J
0.75 J
0 J
Correct Answer
Detailed Explanation
The work-energy theorem states that the change in kinetic energy is equal to the work done by the force. Integrating F_r from x = 0.1 m to x = 2.01 m gives the work done, which is negative, reducing the initial kinetic energy of 2 J.
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