Physics-Work-Energy Theorem

NEET Physics Work-Energy Theorem MCQ Question

Type: MCQ-numerical-Hard-Class 11

A block of mass 2 kg is initially at rest on a frictionless horizontal surface. A variable force F(x) = 3x N is applied to it, where x is the displacement in meters. What is the work done by this force when the block is displaced from x = 0 to x = 4 m?

A

32 J

B

24 J

C

16 J

D

48 J

Correct Answer

Option A

Detailed Explanation

The work-energy theorem states that the work done by a force is equal to the change in kinetic energy. Here, work done W = 043xdx\int_{0}^{4} 3x \, dx, which evaluates to 32x2\frac{3}{2} x^2 from 0 to 4, resulting in 32 J.

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