NEET Physics Work-Energy Theorem MCQ Question
A block of mass 1 kg is moving on a horizontal surface with an initial speed of 2 m/s. It enters a rough patch where the retarding force is inversely proportional to the position x in the range 0.1 m to 2.01 m. If the constant k is 0.5 J, what is the final kinetic energy of the block as it exits the rough patch?
5 J
0 J
0.5 J
0.0 J
Correct Answer
Detailed Explanation
The work done by the retarding force is the integral of F(x) over the displacement. The initial kinetic energy is 2 J, and the negative work done reduces it by 1.5 J, leaving 0.5 J.
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