NEET Physics Work Done by Forces MCQ Question
A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a rough surface with a coefficient of kinetic friction of 0.1. What is the work done by the applied force in 10 seconds?
140 J
70 J
35 J
105 J
Correct Answer
Detailed Explanation
The work done by the applied force is calculated using the formula W = F * d. Here, the force F is 7 N and the displacement d is calculated using the equation of motion under constant acceleration, considering friction.
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