Physics-Work Done by Forces

NEET Physics Work Done by Forces MCQ Question

Type: MCQ-numerical-Easy-Class 11

A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with a coefficient of kinetic friction of 0.1. What is the work done by the applied force in 10 seconds?

A

140 J

B

70 J

C

35 J

D

200 J

Correct Answer

Option A

Detailed Explanation

The work done by a constant force is given by the product of the force and the displacement in the direction of the force. Here, the work done by the applied force is 7 N multiplied by the displacement over 10 seconds. The displacement can be calculated using the equation of motion.

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