NEET Physics Work Done by Forces MCQ Question
A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with a coefficient of kinetic friction of 0.1. What is the work done by the applied force in 10 seconds?
140 J
70 J
35 J
200 J
Correct Answer
Detailed Explanation
The work done by a constant force is given by the product of the force and the displacement in the direction of the force. Here, the work done by the applied force is 7 N multiplied by the displacement over 10 seconds. The displacement can be calculated using the equation of motion.
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