NEET 2015 Physics Conservation of Energy MCQ Question
Two particles of masses m₁, m₂ move with initial velocities u₁ and u₂. On collision, one of the particles get excited to higher level, after absorbing energy ε. If final velocities of particles be v₁ and v₂ then we must have
m₁u₁² + m₂u₂² - ε = m₁v₁² + m₂v₂²
½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂² - ε
½ m₁u₁² + ½ m₂u₂² - ε = ½ m₁v₁² + ½ m₂v₂²
m₁u₁² + ½ m₂u₂² + ε = ½ m₁v₁² + ½ m₂v₂²
Correct Answer
Detailed Explanation
The conservation of energy principle states that the total energy before and after the collision must be equal, accounting for the absorbed energy ε.
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