NEET Physics Wave Equation MCQ Question with Solution

In the wave equation $y = 0.5 \sin \left( \frac{2\pi}{\lambda} (400t - x) \right)$ the velocity of the wave will be :

A

200 m/s

B

$200\sqrt{2} \text{ m/s}$

C

400 m/s

D

$400\sqrt{2} \text{ m/s}$

Correct Answer

Option C

Detailed Explanation

The wave equation is of the form $y = A \sin(kx - \omega t)$ . The wave speed v is given by $v = \frac{\omega}{k} = \frac{400}{1} = 400 \text{ m/s}$ .

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