NEET2017Physics-Oscillations
NEET 2017 Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Hard-Class 11
A particle executes linear simple harmonic motion with amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
A
√3/π
B
√3/2π
C
4π/√5
D
√5/3
Correct Answer
Option C
Detailed Explanation
Using the equations of SHM, v = ω√(A² - x²) and a = ω²x, equating the magnitudes gives the time period T = 2π/ω = √3/π.
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