NEET Physics Young's Double Slit Experiment MCQ Question
A monochromatic light of frequency 500 THz is incident on the slits of a Young's double slit experiment. If the distance between the slits is 0.2 mm and the screen is placed at a distance 1 m from the slits, the width of 10 fringes will be:
5 mm
15 mm
30 mm
3 mm
Correct Answer
Detailed Explanation
The fringe width β is given by β = λD/d. Here, λ = c/f = 3 × 10⁸/500 × 10¹² m, D = 1 m, d = 0.2 × 10⁻³ m. Thus, β = 3 × 10⁸/500 × 10¹² × 1/0.2 × 10⁻³ = 3 mm. For 10 fringes, width = 10 × 3 = 30 mm.
Found an issue with this question?
Related Questions
More from Wave Optics
More from
In a Young's double-slit experiment, the distance between the slits is 0.025 mm, the screen is placed 5 cm away, and the wavelength of light used is 5...
Match Column-I with Column-II. Column-I Column-II (a) Coherent sources (i) Produce interference patterns (b) Incoherent sources (ii) Intensi...
Consider a diagram where spheres of radius vt are drawn from each point on a spherical wavefront, and a common tangent is drawn to all these spheres. ...