NEET2013Physics-Wave Optics
NEET 2013 Physics Young's Double Slit Experiment MCQ Question
Type: MCQ-conceptual-Medium-Class 12
In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width:
A
is halved
B
become four times
C
remains unchanged
D
is doubled
Correct Answer
Option B
Detailed Explanation
The fringe width in Young's double slit experiment is given by β = λD/d, where D is the distance between the slits and the screen, and d is the separation between the slits. Doubling D and halving d makes the fringe width four times.
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