NEET 2019 Physics Error Analysis MCQ Question
In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2%, 3% and 4% respectively. Then the maximum percentage of error in the measurement X, where X = A²B¹/²C³D², will be:
10%
10%
(13/3)%
16%
Correct Answer
Detailed Explanation
The maximum percentage error in X is calculated using the formula: ΔX/X = 2(ΔA/A) + 0.5(ΔB/B) + 3(ΔC/C) + 2(ΔD/D). Substituting the given errors, we get 2(1%) + 0.5(2%) + 3(3%) + 2(4%) = 16%.
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