Physics-Isothermal & Adiabatic Processes
NEET Physics Isothermal & Adiabatic Processes MCQ Question
Type: MCQ-numerical-Easy-Class 11
An ideal gas expands isothermally and reversibly from an initial volume of 2 L to a final volume of 10 L at a temperature of 25 °C. Calculate the work done by the gas if the number of moles is 1 mol. (Given: R = 8.314 J/mol·K)
A
-1,908 J
B
-2,303 J
C
-3,456 J
D
-4,567 J
Correct Answer
Option A
Detailed Explanation
For isothermal reversible expansion, work done w = -nRT ln(Vf/Vi). Substituting n = 1 mol, R = 8.314 J/mol·K, T = 298 K, Vi = 2 L, and Vf = 10 L, we calculate w = -1,908 J.
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