NEET Physics Heat Engines MCQ Question
Calculate the change in internal energy when 1 mol of water is vaporized at 1 bar pressure and 100°C, given that the enthalpy change is 41.00 kJ/mol and the ideal gas constant is 8.3 J/mol K.
37.904 kJ/mol
44.01 kJ/mol
41.53 kJ/mol
096 kJ/mol
Correct Answer
Detailed Explanation
The change in internal energy is calculated using the formula ∆U = ∆H - ∆ngRT with given values: ∆H = 41.00 kJ/mol, ∆ng = 1, R = 8.3 J/mol K, T = 373 K, which results in ∆U = 37.904 kJ/mol.
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