NEET Physics Heat Engines MCQ Question
What is the change in internal energy (ΔU) when 1 mol of water is vaporized at 1 bar pressure and 100°C, given that the enthalpy change (ΔH) is 41.00 kJ mol⁻¹ and the ideal gas constant R is 8.3 J mol⁻¹ K⁻¹?
37.904 kJ mol⁻¹
41.00 kJ mol⁻¹
096 kJ mol⁻¹
44.10 kJ mol⁻¹
Correct Answer
Detailed Explanation
Using the formula ΔU = ΔH - ΔngRT and substituting the values ΔH = 41.00 kJ mol⁻¹, Δng = 1, R = 8.3 J mol⁻¹ K⁻¹, T = 373 K, we get ΔU = 37.904 kJ mol⁻¹.
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