Physics-Heat Engines
NEET Physics Heat Engines MCQ Question
Type: MCQ-numerical-Easy-Class 11
If a heat engine absorbs 44.01 kJ of heat from a reservoir, what is the change in internal energy when the work done by the engine is 2.48 kJ?
A
41.53 kJ
B
46.49 kJ
C
44.01 kJ
D
48 kJ
Correct Answer
Option A
Detailed Explanation
The change in internal energy (ΔU) is calculated using ΔU = q - w, where q is the heat absorbed and w is the work done. Thus, ΔU = 44.01 kJ - 2.48 kJ = 41.53 kJ.
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