Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Medium-Class 11
Given the reaction C(graphite, s) + 2 S(l) → CS₂(l) with ∆rH⁰ = +128.5 kJ mol⁻¹, calculate the enthalpy change if 2 moles of carbon disulfide (CS₂) are formed.
A
+257.0 kJ
B
+128.5 kJ
C
-257.0 kJ
D
-128.5 kJ
Correct Answer
Option A
Detailed Explanation
The enthalpy change given is for the formation of 1 mole of CS₂. For 2 moles, the enthalpy change will be 2 × 128.5 kJ mol⁻¹ = +257.0 kJ.
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