Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Hard-Class 11
Given the reaction 1/2 N2 (g) + O2 (g) → NO2 (g) with a standard enthalpy change (∆rH ) of +33.2 kJ mol–1, calculate the enthalpy change (∆rH) for the reverse reaction NO2 (g) → 1/2 N2 (g) + O2 (g).
A
-33.2 kJ mol–1
B
+33.2 kJ mol–1
C
0 kJ mol–1
D
+66.4 kJ mol–1
Correct Answer
Option A
Detailed Explanation
Based on the NCERT context, reversing a reaction changes the sign of the enthalpy change. Thus, ∆rH for NO2 (g) → 1/2 N2 (g) + O2 (g) is -33.2 kJ mol–1.
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