NEET Physics Thermal Expansion MCQ Question
A steel rod of initial length 1.0 m is heated from 27°C to 45°C. If the coefficient of linear expansion for steel is 1.2 × 10⁻⁵ K⁻¹, what is the increase in its length?
16 × 10⁻⁴ m
44 × 10⁻⁴ m
92 × 10⁻⁴ m
88 × 10⁻⁴ m
Correct Answer
Detailed Explanation
The increase in length, Δl, is given by Δl = αₗ × l × ΔT, where αₗ is the coefficient of linear expansion, l is the initial length, and ΔT is the change in temperature. Substituting the given values, Δl = 1.2 × 10⁻⁵ × 1.0 × 18 = 2.16 × 10⁻⁴ m.
Found an issue with this question?
Related Questions
More from Thermal Expansion
More from
Four rods of same material with different radii r and length are used to connect two reservoirs of heat at different temperatures. Which one will cond...
Match Column-I with Column-II. Column-I Column-II (a) Kelvin scale (i) 0 K (b) Water as coolant (ii) Heats up slowly (c) Heat of vaporisa...
What is the SI unit of specific heat capacity?