NEET Physics Temperature & Heat MCQ Question
How much heat is required to convert 2 kg of ice at -10°C to water at 0°C? The specific heat capacity of ice is 2100 J kg⁻¹ K⁻¹ and the latent heat of fusion of ice is 3.35 × 10⁵ J kg⁻¹.
42000 J
84000 J
700000 J
742000 J
Correct Answer
Detailed Explanation
To calculate the total heat required, first calculate the heat to raise the temperature of ice to 0°C using Q = mcΔT. Then add the heat required for the phase change using Q = mL. Total heat = (2 kg)(2100 J/kg/K)(10 K) + (2 kg)(3.35 × 10⁵ J/kg) = 42000 J + 670000 J = 742000 J.
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