Physics-Temperature & Heat
NEET Physics Temperature & Heat Match the Following Question
Type: Match the Following-match the column-Medium-Class 11
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Heat required to melt ice at 0 °C | (i) 1005000 J |
| (b) Heat required to convert water at 0 °C to water at 100 °C | (ii) 1255800 J |
| (c) Heat required to convert water at 100 °C to steam at 100 °C | (iii) 6768000 J |
| (d) Total heat for the entire process | (iv) 9.1 × 10^6 J |
A
a-i, b-ii, c-iii, d-iv
B
a-ii, b-i, c-iv, d-iii
C
a-i, b-iii, c-ii, d-iv
D
a-iv, b-ii, c-i, d-iii
Correct Answer
Option A
Detailed Explanation
The heat required to melt ice at 0 °C is calculated as 1005000 J, converting water at 0 °C to 100 °C requires 1255800 J, converting water at 100 °C to steam at 100 °C is 6768000 J, and the total heat for the entire process is 9.1 × 10^6 J, as derived from the NCERT context.
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