NEET Physics Heat Transfer MCQ Question
A metal rod of length 0.1 m and cross-sectional area 0.02 m² is subjected to a temperature difference of 100 K between its ends. If the thermal conductivity of the rod is 91.6 W/mK, what is the rate of heat transfer through the rod?
183.2 W
91.6 W
1832 W
916 W
Correct Answer
Detailed Explanation
The rate of heat transfer by conduction is given by the formula Q/t = k * A * (ΔT/L), where k is thermal conductivity, A is the cross-sectional area, ΔT is the temperature difference, and L is the length of the rod. Plugging in the values: Q/t = 91.6 * 0.02 * (100/0.1) = 916 W.
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