NEET2016Physics-Rotational Motion
NEET 2016 Physics Moment of Inertia MCQ Question
Type: MCQ-conceptual-Medium-Class 11
From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre?
A
11 MR²/32
B
9 MR²/32
C
15 MR²/32
D
13 MR²/32
Correct Answer
Option D
Detailed Explanation
The moment of inertia of the entire disc is MR²/2. The moment of inertia of the removed part is (MR²/8) + (MR²/32) = 5MR²/32. Subtracting this from the whole disc gives 11MR²/32.
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