Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Easy-Class 11
If a spring with a spring constant k = 200 N/m is compressed by 0.05 m, what is the potential energy stored in the spring?
A
0.25 J
B
0.50 J
C
0.125 J
D
0.05 J
Correct Answer
Option C
Detailed Explanation
The potential energy stored in a spring is given by the formula (1/2)kx^2. Using k = 200 N/m and x = 0.05 m, the potential energy is (1/2)200(0.05)^2 = 0.125 J.
Found an issue with this question?