Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Medium-Class 11
A block of mass 4 kg is released from rest at the top of a smooth inclined plane of height 5 m. What is the speed of the block at the bottom of the inclined plane? (Use g = 9.8 m/s²)
A
9.9 m/s
B
7.0 m/s
C
14.0 m/s
D
10.0 m/s
Correct Answer
Option A
Detailed Explanation
The speed of the block at the bottom is given by v = sqrt(2gh). Substituting g = 9.8 m/s² and h = 5 m, v = sqrt(2 * 9.8 * 5) = 9.9 m/s.
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