Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Hard-Class 11
A block attached to a horizontal massless spring is displaced 2.00 m from its equilibrium position. If the spring constant is 250 N/m, what is the potential energy stored in the spring at maximum compression?
A
500 J
B
250 J
C
1000 J
D
125 J
Correct Answer
Option A
Detailed Explanation
The potential energy stored in the spring is given by V = 1/2 k x^2. Substituting k = 250 N/m and x = 2.00 m, we get V = 1/2 * 250 * (2.00)^2 = 500 J.
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