Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Medium-Class 11
Calculate the work done by a force F = (2i + 3j - 4k) acting on a particle that undergoes a displacement d = (6i - j + 2k) in SI units.
A
5 J
B
6 J
C
12 J
D
8 J
Correct Answer
Option C
Detailed Explanation
The work done by a force is calculated using the dot product: W = F.d = (26) + (3-1) + (-4*2) = 12 J.
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