Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-numerical-Hard-Class 11

A particle is projected vertically upwards from the ground with initial velocity v0v_0. If the particle reaches a maximum height HH, what is the initial velocity v0v_0 in terms of HH and gg, the acceleration due to gravity?

A

v0=2gHv_0 = \sqrt{2gH}

B

v0=gHv_0 = gH

C

v0=gH2v_0 = \frac{gH}{2}

D

v0=gHv_0 = \sqrt{gH}

Correct Answer

Option A

Detailed Explanation

From the conservation of mechanical energy, all potential energy at height HH comes from the initial kinetic energy. Thus, 12mv02=mgH\frac{1}{2}mv_0^2 = mgH, leading to v0=2gHv_0 = \sqrt{2gH}.

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